Optimal. Leaf size=270 \[ -\frac{\sqrt{2 x+1} (5-4 x)}{31 \left (5 x^2+3 x+2\right )}-\frac{1}{31} \sqrt{\frac{1}{310} \left (47 \sqrt{35}-218\right )} \log \left (5 (2 x+1)-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )+\frac{1}{31} \sqrt{\frac{1}{310} \left (47 \sqrt{35}-218\right )} \log \left (5 (2 x+1)+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )-\frac{1}{31} \sqrt{\frac{2}{155} \left (218+47 \sqrt{35}\right )} \tan ^{-1}\left (\frac{\sqrt{10 \left (2+\sqrt{35}\right )}-10 \sqrt{2 x+1}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )+\frac{1}{31} \sqrt{\frac{2}{155} \left (218+47 \sqrt{35}\right )} \tan ^{-1}\left (\frac{10 \sqrt{2 x+1}+\sqrt{10 \left (2+\sqrt{35}\right )}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right ) \]
[Out]
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Rubi [A] time = 1.1621, antiderivative size = 270, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 7, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.318 \[ -\frac{\sqrt{2 x+1} (5-4 x)}{31 \left (5 x^2+3 x+2\right )}-\frac{1}{31} \sqrt{\frac{1}{310} \left (47 \sqrt{35}-218\right )} \log \left (5 (2 x+1)-\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )+\frac{1}{31} \sqrt{\frac{1}{310} \left (47 \sqrt{35}-218\right )} \log \left (5 (2 x+1)+\sqrt{10 \left (2+\sqrt{35}\right )} \sqrt{2 x+1}+\sqrt{35}\right )-\frac{1}{31} \sqrt{\frac{2}{155} \left (218+47 \sqrt{35}\right )} \tan ^{-1}\left (\frac{\sqrt{10 \left (2+\sqrt{35}\right )}-10 \sqrt{2 x+1}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right )+\frac{1}{31} \sqrt{\frac{2}{155} \left (218+47 \sqrt{35}\right )} \tan ^{-1}\left (\frac{10 \sqrt{2 x+1}+\sqrt{10 \left (2+\sqrt{35}\right )}}{\sqrt{10 \left (\sqrt{35}-2\right )}}\right ) \]
Antiderivative was successfully verified.
[In] Int[(1 + 2*x)^(3/2)/(2 + 3*x + 5*x^2)^2,x]
[Out]
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Rubi in Sympy [A] time = 69.9454, size = 379, normalized size = 1.4 \[ - \frac{\left (- 4 x + 5\right ) \sqrt{2 x + 1}}{31 \left (5 x^{2} + 3 x + 2\right )} - \frac{\sqrt{14} \left (- \frac{2 \sqrt{35}}{5} + 7\right ) \log{\left (2 x - \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \sqrt{2 x + 1}}{5} + 1 + \frac{\sqrt{35}}{5} \right )}}{434 \sqrt{2 + \sqrt{35}}} + \frac{\sqrt{14} \left (- \frac{2 \sqrt{35}}{5} + 7\right ) \log{\left (2 x + \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \sqrt{2 x + 1}}{5} + 1 + \frac{\sqrt{35}}{5} \right )}}{434 \sqrt{2 + \sqrt{35}}} + \frac{\sqrt{35} \left (- \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \left (- \frac{4 \sqrt{35}}{5} + 14\right )}{10} + \frac{14 \sqrt{10} \sqrt{2 + \sqrt{35}}}{5}\right ) \operatorname{atan}{\left (\frac{\sqrt{10} \left (\sqrt{2 x + 1} - \frac{\sqrt{20 + 10 \sqrt{35}}}{10}\right )}{\sqrt{-2 + \sqrt{35}}} \right )}}{217 \sqrt{-2 + \sqrt{35}} \sqrt{2 + \sqrt{35}}} + \frac{\sqrt{35} \left (- \frac{\sqrt{10} \sqrt{2 + \sqrt{35}} \left (- \frac{4 \sqrt{35}}{5} + 14\right )}{10} + \frac{14 \sqrt{10} \sqrt{2 + \sqrt{35}}}{5}\right ) \operatorname{atan}{\left (\frac{\sqrt{10} \left (\sqrt{2 x + 1} + \frac{\sqrt{20 + 10 \sqrt{35}}}{10}\right )}{\sqrt{-2 + \sqrt{35}}} \right )}}{217 \sqrt{-2 + \sqrt{35}} \sqrt{2 + \sqrt{35}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((1+2*x)**(3/2)/(5*x**2+3*x+2)**2,x)
[Out]
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Mathematica [C] time = 0.83775, size = 145, normalized size = 0.54 \[ \frac{\sqrt{2 x+1} (4 x-5)}{31 \left (5 x^2+3 x+2\right )}+\frac{2 \left (62-39 i \sqrt{31}\right ) \tan ^{-1}\left (\frac{\sqrt{10 x+5}}{\sqrt{-2-i \sqrt{31}}}\right )}{961 \sqrt{-10-5 i \sqrt{31}}}+\frac{2 \left (62+39 i \sqrt{31}\right ) \tan ^{-1}\left (\frac{\sqrt{10 x+5}}{\sqrt{-2+i \sqrt{31}}}\right )}{961 \sqrt{5 i \left (\sqrt{31}+2 i\right )}} \]
Antiderivative was successfully verified.
[In] Integrate[(1 + 2*x)^(3/2)/(2 + 3*x + 5*x^2)^2,x]
[Out]
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Maple [B] time = 0.034, size = 485, normalized size = 1.8 \[ 16\,{\frac{1}{ \left ( 1+2\,x \right ) ^{2}-8/5\,x+3/5} \left ({\frac{ \left ( 1+2\,x \right ) ^{3/2}}{310}}-{\frac{7\,\sqrt{1+2\,x}}{620}} \right ) }+{\frac{2\,\sqrt{20+10\,\sqrt{35}}\sqrt{35}}{4805}\ln \left ( 5+10\,x+\sqrt{35}-\sqrt{1+2\,x}\sqrt{20+10\,\sqrt{35}} \right ) }-{\frac{39\,\sqrt{20+10\,\sqrt{35}}}{9610}\ln \left ( 5+10\,x+\sqrt{35}-\sqrt{1+2\,x}\sqrt{20+10\,\sqrt{35}} \right ) }+{\frac{ \left ( 80+40\,\sqrt{35} \right ) \sqrt{35}}{4805\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}-\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }-{\frac{780+390\,\sqrt{35}}{4805\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}-\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }+{\frac{4\,\sqrt{35}}{31\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}-\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }-{\frac{2\,\sqrt{20+10\,\sqrt{35}}\sqrt{35}}{4805}\ln \left ( 5+10\,x+\sqrt{35}+\sqrt{1+2\,x}\sqrt{20+10\,\sqrt{35}} \right ) }+{\frac{39\,\sqrt{20+10\,\sqrt{35}}}{9610}\ln \left ( 5+10\,x+\sqrt{35}+\sqrt{1+2\,x}\sqrt{20+10\,\sqrt{35}} \right ) }+{\frac{ \left ( 80+40\,\sqrt{35} \right ) \sqrt{35}}{4805\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}+\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }-{\frac{780+390\,\sqrt{35}}{4805\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}+\sqrt{20+10\,\sqrt{35}} \right ) } \right ) }+{\frac{4\,\sqrt{35}}{31\,\sqrt{-20+10\,\sqrt{35}}}\arctan \left ({\frac{1}{\sqrt{-20+10\,\sqrt{35}}} \left ( 10\,\sqrt{1+2\,x}+\sqrt{20+10\,\sqrt{35}} \right ) } \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((1+2*x)^(3/2)/(5*x^2+3*x+2)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (2 \, x + 1\right )}^{\frac{3}{2}}}{{\left (5 \, x^{2} + 3 \, x + 2\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*x + 1)^(3/2)/(5*x^2 + 3*x + 2)^2,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.272005, size = 1297, normalized size = 4.8 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*x + 1)^(3/2)/(5*x^2 + 3*x + 2)^2,x, algorithm="fricas")
[Out]
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Sympy [A] time = 77.1158, size = 211, normalized size = 0.78 \[ \frac{64 \left (2 x + 1\right )^{\frac{3}{2}}}{- 992 x + 620 \left (2 x + 1\right )^{2} + 372} - \frac{224 \left (2 x + 1\right )^{\frac{3}{2}}}{- 6944 x + 4340 \left (2 x + 1\right )^{2} + 2604} - \frac{128 \sqrt{2 x + 1}}{5 \left (- 992 x + 620 \left (2 x + 1\right )^{2} + 372\right )} - \frac{3024 \sqrt{2 x + 1}}{5 \left (- 6944 x + 4340 \left (2 x + 1\right )^{2} + 2604\right )} + \frac{64 \operatorname{RootSum}{\left (407144088666112 t^{4} + 3325152256 t^{2} + 11045, \left ( t \mapsto t \log{\left (\frac{33312534528 t^{3}}{235} + \frac{166784 t}{235} + \sqrt{2 x + 1} \right )} \right )\right )}}{5} - \frac{112 \operatorname{RootSum}{\left (19950060344639488 t^{4} + 498437272576 t^{2} + 10878125, \left ( t \mapsto t \log{\left (- \frac{11049511452672 t^{3}}{2205125} + \frac{307918256 t}{2205125} + \sqrt{2 x + 1} \right )} \right )\right )}}{5} + \frac{16 \operatorname{RootSum}{\left (1722112 t^{4} + 1984 t^{2} + 5, \left ( t \mapsto t \log{\left (- \frac{27776 t^{3}}{5} + \frac{108 t}{5} + \sqrt{2 x + 1} \right )} \right )\right )}}{5} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((1+2*x)**(3/2)/(5*x**2+3*x+2)**2,x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (2 \, x + 1\right )}^{\frac{3}{2}}}{{\left (5 \, x^{2} + 3 \, x + 2\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((2*x + 1)^(3/2)/(5*x^2 + 3*x + 2)^2,x, algorithm="giac")
[Out]